Respuesta :
Answer:
2 and one half
Step-by-step explanation:
Given
ABC = (4,4),(7,8),(10,4)
A'B'C' = (10,10),(17,20),(25,10)
Required:
Find the Scale Factor
Let the scale factor be represented by s
The relationship between ABC, A'B'C' and s is given as
[tex]s(ABC) = A'B'C'[/tex]
From the given parameters;
A = (4,4) when A' = (10,10)
Using this values;we have
[tex]s * (4,4) = (10,10)[/tex]
Divide both sides by (4,4)
[tex]\frac{s * (4,4)}{(4,4)} = \frac{(10,10)}{(4,4)}[/tex]
[tex]s = \frac{(10,10)}{(4,4)}[/tex]
Divide 10 by 4; This gives 2.5
So,
s = 2.5
Using Point B and B'
B = (7,8) when A' = (17,20)
[tex]s * (7,8) = (17,20)[/tex]
Divide both sides by (7,8)
[tex]\frac{s * (7,8)}{(7,8)} = \frac{(17,20)}{(7,8)}[/tex]
[tex]s = \frac{(17,20)}{(7,8)}[/tex]
Divide 17 by 7 and 20 by 8; This gives 2.5
So,
s = 2.5
Using Point C and C'
C = (10,4) when C' = (25,10)
[tex]s * (10,4) = (25,10)[/tex]
Divide both sides by (10,4)
[tex]\frac{s * (10,4)}{(10,4)} = \frac{(25,10)}{(10,4)}[/tex]
[tex]s= \frac{(25,10)}{(10,4)}[/tex]
Divide 25 by 10 and 10 by 4; This gives 2.5
So,
s = 2.5
Hence, the scale factor is 2 and one-half([tex]2\frac{1}{2}[/tex])