What is the solution to the equation below?

Answer:
answer D
Step-by-step explanation:
First we simplify (using the rule [tex]\log a - \log b = \log \frac{a}{b}[/tex])
[tex]\log_6 \frac{4x^2}{x} = \log_6 4x = 2[/tex]
Then realize that this means (using the rule [tex]\log_a(x) = q \implies a^q = x[/tex]):
[tex]6^2 = 4x[/tex]
so x = 36/4 = 9