Respuesta :
The molarity of the potassium hydroxide required to neutralize 60.0 mL of 0.0100 M [tex]H_3PO_4[/tex] is 0.02M.
How to calculate molarity?
The molarity of a solution can be calculated using the following formula:
[tex]M_aV_a = M_bV_b[/tex]
Where;
[tex]M_a[/tex] = concentration of acid
[tex]M_b[/tex] = concentration of base
[tex]V_a[/tex]= volume of acid
[tex]V_b[/tex] = volume of base
60 × 0.0100 = 30 ×[tex]M_b[/tex]
0.6 = 30 [tex]M_b[/tex]
[tex]M_b[/tex] = 0.6/30
[tex]M_b[/tex] = 0.02M
Therefore, the molarity of the potassium hydroxide required to neutralize 60.0 mL of 0.0100 M [tex]H_3PO_4[/tex] is 0.02M.
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