Question

23.24 mL of a solution of the acid H2SO4 is titrated, and 56.10 mL of 0.7200-M NaOH is required to reach the equivalence point. Calculate the original concentration of the acid solution. g

Answer 1

Answer : The original concentration of the acid solution is 0.869 M

Explanation :

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2SO_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=?\\V_1=23.24mL\\n_2=1\\M_2=0.7200M\\V_2=56.10mL$

Putting values in above equation, we get:

$2\times M_1\times 23.24=1\times 0.7200\times 56.10\\\\M_1=0.869M$

Therefore, the original concentration of the acid solution is 0.869 M