Question

Is the solution shown below correct? Explain.

9x+2=8x2+6x

Negative 8 x squared + 3 x + 2 = 0. x = StartFraction negative 3 plus-or-minus StartRoot (3) squared minus (4) (negative 8) (2) EndRoot Over negative 16 EndFraction. x = StartFraction negative 3 plus-or-minus StartRoot 9 minus (64) EndRoot Over negative 16 EndFraction. x = StartFraction 3 plus-or-minus StartRoot 55 Endroot i Over 16 EndFraction.

Answer 1

Answer:

It is wrong

Step-by-step explanation:

What we have is as follows;

9x + 2 = 8x^2 + 6x

Bringing 9x + 2 yo the right hand side, we have;

8x^2 + 6x -9x -2 = 0

8x^2 -3x -2 = 0

So what is used here is the quadratic formula and we want to try to see if it was used correctly.

The form we have in the question is however;

-8x^2+ 3x + 2 = 0

which is obtained by taking the right hand side of the equation to the left

Now;

using the quadratic formula;

x = -b ± √(b^2 -4ac)/2a

where a is -8

b = 3

c = 2

Thus we have

-3 ± √(9 - 4(-8)2)/2(-8)

-3 ± √(9 + 64)/(-16)

So where is wrong is in the square root

what we are supposed to have is 9 + 64 = 73 and not otherwise

Answer 2

Answer:

No because the formula was not simplified incorrectly. And the 64 should have been added. And the radicand should be 73. Their should also be two roots due to the equation.

Step-by-step explanation:

Your welcome