Answer:
Cost function:
[tex]C(x)=790+2.88x[/tex]
Revenue function
[tex]R(x)=6x[/tex]
Profit function
[tex]P(x)=3.12x-790[/tex]
Dozens needed for a specific profit P
[tex]x=\dfrac{P-790}{3.12}[/tex]
If 150 dozen cookies are sold the profit is negative, so the business is loosing $322.
Step-by-step explanation:
We can list the costs as:
- Fixed monthly cost, $790/month.
- Variable costs, $0.24/cookie, which are (12*0.24) = $2.88 a dozen.
Then, we can write the cost function C(x) as:
[tex]C(x)=790+2.88x[/tex]
being C(x): the monthly cost and x: the number of dozens produced per month.
The revenue can be calculated as the price ($6 a dozen) multiplied by the number of dozens x:
[tex]R(x)=6x[/tex]
The profit can be calculated substracting the total cost C(x) from the revenue R(x).
[tex]P(x)=R(x)-C(x)\\\\P(x)=(6x)-(790+2.88x)=(6-2.88)x-790\\\\P(x)=3.12x-790[/tex]
The number of cookies (in dozens) that must be produced and sold for a monthly profit can be calculated from the previous equation for P(x).
For a monthly profit P, the number of dozens that need to be sold are:
[tex]P=3.12x-790\\\\P+790=3.12x\\\\\\x=\dfrac{P-790}{3.12}[/tex]
If 150 dozen cookies are sold, the profit made is:
[tex]P(150)=3.12(150)-790=468-790=-322[/tex]
The profit is negative, so the business is loosing $322.