Question

Let $\overline{XY}$ be a tangent to a circle, and let $\overline{XBA}$ be a secant of the circle, as shown below. If $AX = 15$ and $XY = 9$, then what is $AB$?

Answer 1

Answer:

AB=5.4 units

Step-by-step explanation:

We using the theorem of intersecting tangent and secant to solve this.

By this theorem:

$XY^2=XB \times AX\\9^2=15(15-XB)\\81=225-15XB\\15XB=144\\XB=9.6\\ Therefore:\\AB=AX-XB\\AB=15-9.6\\AB=5.4 units$

Answer 2

Answer:

Its 9.6, the other guy got it wrong, he already got it but accidentally added a step. Its 9.6 :)

Step-by-step explanation:

trust me :).