Question

A man is 50 years old. 8years ago, he was seven times as old as his daughter. How old is the daughter now?


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Answer 1

Answer:

14 years old.

Step-by-step explanation:

The man was 42 years old 8 years ago.

When he was 42, he was 7 times as old as his daughter.

Let his daughter's age be x.

$42=7x\\42/7=x\\6=x$

Her daughter was 6 years old 8 years ago.

8 years later she would be:

$6+8$

$=14$

14 years old.

Answer 2

Answer:

14 years

Step-by-step explanation:

Let the daughter's age before 8 years be y

The man is 50 years old.

8 years ago, he was

=> 50-8 = 42 years

Also,

8 years ago,

7(y) = 42

=> Dividing both sides by 7

y = 6

Now after 8 years,

The daughter's age is,

=> 6 + 8 = 14 years