Answer:
[tex]n^2+3\\(n+1)^2[/tex]
Step-by-step explanation:
[tex]n^2+3\\1^2+3=4\\2^2+3=7\\3^2+3=12[/tex]
[tex](n+1)^2\\(1+1)^2=4\\(2+1)^2=9\\(3+1)^2=16[/tex]