Question

I'm confused can someone help ? Suppose we are told that the mean IQ of a population is μ = 100 and the standard deviation is σ = 10. Draw a normal distribution to represent the data percentage of data between 80 and 120.

Answer 1

Answer:

just multiply 80 and 120 then you get your answer

Answer 2

The data percentage of 34.13% of the population would be between 80 and 120.

How to get the z scores?

If we've got a normal distribution, then we can convert it to a standard normal distribution and its values will give us the z score.

$Z = \dfrac{X - \mu}{\sigma}, \\\\Z \sim N(0,1)$

Given that μ = 100, σ = 10:

For x = 80:

$Z = \dfrac{80 - 100}{10}, \\\\Z = 2$

For x = 120:

$Z = \dfrac{120 - 100}{10}, \\\\Z = 2$

Therefore, the normal distribution table: P(80< x < 120) = P(0 < z < 1) = P(z < 1) - P(z < 0) = 0.8413 - 0.5 = 34.13%

Hence 34.13% of the population would be between 80 and 120.

Learn more about z-score here:

https://brainly.com/question/21262765

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