Question

A line is perpendicular to y = 4x – 2
and intersects the point (4, -11).
What is the equation of this
perpendicular line?

Answer 1

Answer:

$y = (-\frac{1}{4} )x-10$

Step-by-step explanation:

Perpendicular => So the slope will be the negative reciprocal of this slope

Slope = m = $-\frac{1}{4}$

Point = (x,y) = (4,-11)

So, x = 4, y = -11

Putting this in slope intercept equation to get b

$y = mx +b$

-11 = $(-\frac{1}{4} )$(4) + b

-11 = -1 + b

b = -11+1

b = -10

Now putting the slope and y-intercept in the equation to get the required slope intercept equation.

$y = (-\frac{1}{4} )x-10$