Question

PLZ HURRY

The graphed line shown below is y = negative 3 x + 6. On a coordinate plane, a line goes through points (1, 3) and (2, 0). Which equation, when graphed with the given equation, will form a system that has no solution? A)y = 3 x + 6 B)y = negative 3 (x + 6) C)y = negative 3 (x minus 2) D)y = 3 (x minus 2).

Answer 1

Answer:

y = -3 (x + 6)   when graphed with the given equation, will form a system that has no solution

Step-by-step explanation:

Given line equation: $y=-3x+6$

We are supposed to find Which equation, when graphed with the given equation, will form a system that has no solution.

We know that a system of two linear equations has no solution if and only if the two equations have the same slope, but not the same y-intercept.

General equation of line = $y=mx+c$

A)y = 3 x + 6

So, Slope = 3

B)y = -3 (x + 6)

y=-3x-18

So, slope=-3

C)y=-3(x-2)

y=-3x+6

So, Slope = -3

D)y=3(x-2)

Slope =3

So, B has the same slope but different intercept

So,y = -3 (x + 6)   when graphed with the given equation, will form a system that has no solution

Answer 2

Answer:

B) y= -3(x+6)

Step-by-step explanation