Question

What is the mass percent of glucose solute of a solution that is composed of 243g of glucose and 4.52 L of water? The density of water is 1.00g/mL.

Answer 1

Answer:

5.11 %

Explanation:

Step 1: Convert the volume of water to millimeters

We will use the relationship 1 L = 1,000 mL.

$4.52 L \times \frac{1,000mL}{1L} = 4.52 \times 10^{3} mL$

Step 2: Calculate the mass corresponding to 4.52 × 10³ mL of water

The density of water is 1.00 g/mL.

$4.52 \times 10^{3} mL \times \frac{1.00g}{mL} = 4.52 \times 10^{3} g$

Step 3: Calculate the mass of the solution

The mass of the solute (glucose) is 243 g and the mass of the solvent (water) is 4.52 × 10³ g. The mass of the solution is:

m(solution) = m(solute) + m(solvent)

m(solution) = 243 g + 4.52 × 10³ g

m(solution) = 4.76 × 10³ g

Step 4: Calculate the mass percent of glucose in the solution

$\% Glucose = \frac{mass\ of\ solute}{mass\ of\ solution} \times 100 \% = \frac{243g}{4.76 \times 10^{3}g} \times 100 \% = 5.11 \%$