Question

what are the roots of -12x^2 11x − 3 = 0?

Answer 1

$x= \frac{-b\pm\sqrt{b^2-4ac}}{2a} \\=\frac{-(-11)\pm\sqrt{(-11)^2-(4\times12\times3)}}{2\times12}\\=\frac{11\pm\sqrt{121-144}}{24}\\=\frac{11\pm\sqrt{-23}}{24}\\=\frac{11+i\sqrt{23}}{24}\ or \ \frac{11-i\sqrt{23}}{24}$12x^2 - 11x + 3 = 0