Question

Determine how many moles of Ba(OH)2 are required to completely neutralize 0.425 mole of HC2H3O2.

Answer 1

Answer : The number of moles of $Ba(OH)_2$ required are, 0.2125 moles.

Explanation : Given,

Moles of $HC_2H_3O_2$ = 0.425 mole

The balanced chemical reaction will be:

$Ba(OH)_2+2HC_2H_3O_2\rightarrow Ba(C_2H_3O_2)_2+2H_2O$

From the balanced chemical reaction we conclude that,

As, 2 moles of $HC_2H_3O_2$ completely neutralize by 1 mole of $Ba(OH)_2$

So, 0.425 moles of $HC_2H_3O_2$ completely neutralize by $\frac{0.425}{2}=0.2125$ mole of $Ba(OH)_2$

Therefore, the number of moles of $Ba(OH)_2$ required are, 0.2125 moles.

Answer 2

The number of moles of Ba(OH)₂ that are required to completely neutralize the 0.425 mole of HC₂H₃O₂ is 0.2125 mole

From the question,

We are to determine the number of moles of Ba(OH)₂ that are required to completely neutralize 0.425 mole of HC₂H₃O₂

First, we will write a balanced chemical equation for the reaction,

The balanced chemical equation for the reaction is

Ba(OH)₂ + 2HC₂H₃O₂ → Ba(C₂H₃O₂)₂ + 2H₂O

This means 1 mole of Ba(OH)₂ is required to completely neutralize 2 moles of HC₂H₃O₂

Now,

Let number of moles of Ba(OH)₂ that would neutralize the HC₂H₃O₂ be x

From the given information

Number of moles of HC₂H₃O₂ = 0.425 mole

Since

1 mole of Ba(OH)₂ is required to completely neutralize 2 moles of HC₂H₃O₂

Then,

x mole of Ba(OH)₂ would be required to completely neutralize 0.425 mole of HC₂H₃O₂

x = $\frac{0.425 \times 1 }{2}$

x = 0.2125

Hence, the number of moles of Ba(OH)₂ that are required to completely neutralize the 0.425 mole of HC₂H₃O₂ is 0.2125 mole

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