Question

Find the values of a , b , c in the equation
(X^5yz^4)^3\x^3yz=x^ay^bz^c

Answer 1

Answer:

  (a, b, c) = (12, 2, 11)

Step-by-step explanation:

We assume you want to simplify ...

  $\dfrac{(x^5yz^4)^3}{x^3yz}=x^{3\cdot 5-3}y^{3\cdot 1-1}z^{3\cdot 4-1}=x^{12}y^2z^{11}$

Compared to (x^a)(y^b)(z^c), we find that ...

  (a, b, c) = (12, 2, 11)

_____

The applicable rules of exponents are ...

  (a^b)^c = a^(bc)

  (ab)^c = (a^c)(b^c)

  (a^b)/(a^c) = a^(b-c)