Question

When 47.2 J of heat is added to 13.4 g of a liquid, its
temperature rises by 1.74 °C.
What is the heat capacity of the liquid?

Answer 1

Answer: 2.02 J/g°C

Explanation:

To find the heat capacity, we have to manipulate the equation for heat.

q=mCΔT becomes C=q/(mΔT) to find heat capacity. Since we are given our values, we can plug in to find C.

$C=\frac{47.2J}{13.4g*1.74°C}$

*Please ignore the capital A in front of the °C. In order to have ° in the equaiton, the A pops up.

$C=2.02J/g°C$