Respuesta :

Answer:

[tex]\sqrt[3]{3}[/tex]

Step-by-step explanation:

Our expression is: [tex]\frac{1}{3} \sqrt[3]{81}[/tex].

Let's focus on the cube root of 81 first. What's the prime factorisation of 81? It's simply: 3 * 3 * 3 * 3, or [tex]3^3*3[/tex]. Put this in for 81:

[tex]\sqrt[3]{81} =\sqrt[3]{3^3*3}=\sqrt[3]{3^3} *\sqrt[3]{3}[/tex]

We know that the cube root of 3 cubed will cancel out to become 3, but the cube root of 3 cannot be further simplified, so we keep that. Our outcome is then:

[tex]\sqrt[3]{3^3} *\sqrt[3]{3}=3\sqrt[3]{3}[/tex]

Now, let's multiply this by 1/3, as shown in the original problem:

[tex]\frac{1}{3}* 3\sqrt[3]{3}=\sqrt[3]{3}[/tex]

Thus, the answer is [tex]\sqrt[3]{3}[/tex].

~ an aesthetics lover

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