Answer:
Step-by-step explanation:
a). Given function is y = [tex]\frac{1}{2}x^3-2x+1[/tex]
At x = -3,
y = [tex]\frac{1}{2}(-3)^3-2(-3)+1[/tex]
y = -13.5 + 6 + 1
y = -6.5
For x = -2,
y = [tex]\frac{1}{2}(-2)^3-2(-2)+1[/tex]
y = -4 + 4 + 1
y = 1
For x = 2
y = [tex]\frac{1}{2}(2)^2-2(2)+1[/tex]
y = 4 - 4 + 1
y = 1
Therefore, table for the given function will be,
x -3 -2 -1 0 1 2
y -6.5 1 2.5 1 -0.5 1
b). From the table given in part (a) we find the points lying on the graph are (-2, 1), (-1, 2.5) and (2, 1).
These points justify the graph (C)
Therefore, graph (C) will be the answer.
