Question

log(1+y) - log(1-y) = log x in 2 decimal places, express y in terms of x

Answer 1

Answer: $y = \frac{x-1}{x+1}$

Step-by-step explanation:

$log(1+y) - log(1-y) = log x \\log\frac{1+y}{1-y} =log x\\x = \frac{1+y}{1-y}\\x(1-y)=1+y\\x-xy=1+y\\x-1 = xy+y\\y(x+1)=x-1\\y=\frac{x-1}{x+1}$

Answer 2

Express y in terms of x.

Log (1+y) - Log (1-y) = Log x