Question

Zn(OH)2 SnO22-Zn SnO32- H2O In the above redox reaction, use oxidation numbers to identify the element oxidized, the element reduced, the oxidizing agent and the reducing agent. name of the element oxidized: name of the element reduced: formula of the oxidizing agent: formula of the reducing agent:

Answer 1

Answer:

Explanation:

Zn(OH)₂ + SnO₂⇄  ZnSnO₃+  H₂O

In this reaction , nothing is oxidised , nor is anything reduced .

oxidation number of Zn in Zn(OH)₂ is + 2 ,

oxidation number of Zn in ZnSnO₃ is also + 2 .

oxidation number of Sn in SnO₂  is + 4 ,

oxidation number of Sn in ZnSnO₃ is also + 4 .

Oxidation no of oxygen and hydrogen also remains unchanged at -2 and + 1

respectively .

So it is not a redox reaction .