Question

Find the value of c that makes the expression a perfect square trinomial. Then write the expression as the square of a binomial.
x^2+7x+c

Answer 1

The question ask to calculate the expression as the square of a binomial and also find the value of c that makes the expression a perfect square and the best answer would be that the value of C is 49/4  and its perfect square is (7/2)^2.  I hope you are satisfied with my answer and feel free to ask for more 

Answer 2

For this case we have the following trinomial:

$x ^ 2 + 7x + c$

To find the value of c that makes the expression a perfect square, we must complete the square.

We have then:

$x ^ 2 + 7x + (\frac{7}{2}) ^ 2$

Rewriting we have:

$x ^ 2 + 7x +\frac{49}{4}$

Therefore the value of c is given by:

$c = \frac{49}{4}$

Then, the expression written as a binomial is:

$(x + \frac{7}{2}) ^ 2$

Answer:

the value of c that makes the expression to perfect square trinomial is:

$c = \frac{49}{4}$

The expression as the square of a binomial is:

$(x + \frac{7}{2}) ^ 2$