Question

Given the equations below what is the value of n/m?
m-6(n+2)=-8
6n+m=16

Answer 1

Answer:

$\frac{1}{10}$

Step-by-step explanation:

$m-6(n+2)=-8\\6n+m=16$

Rearrange the second equation and substitute it into the first equation.

$m=16-6n\\16-6n-6(n+2)=-8\\16-6n-6n-12=-8\\16-12n-12=-8\\4-12n=-8\\4+8=12n\\12=12n\\n=1$

Now we can use our value of n, and substitute it into the second equation to solve for m.

$6(1)+m=16\\6+m=16\\m=10$

Now we can divide our values.

$\frac{n}{m}=\frac{1}{10}$