Question

The graph of g(x) = ax^2 opens downward and is narrower than the graph of f(x) = x^2. Which of the following could be the value of a?

Answer 1

The value of a should be less than -1.

Equation of parabola,

The equation of a parabola is given by the following function,

$y=f(x)=\pm a(x-h)^2+k$

where,

(h, k) denotes the coordinates of its vertex,

a defines how narrower is the parabola, and the "-" or "+" that the parabola will open up or down.

Given to us,

$f(x) = x^2$

$g(x)=ax^2$

Solution

For the parabola,g(x) to be narrower than the parabola f(x) the value of a should be less than 1. also for the parabola to open downward the value of a is needed to be negative.

Hence, the value of a should be less than -1.

Learn more about Equation of parabola:

https://brainly.com/question/4443998