The area of a rectangle is 112 units squared.
The length is 7 and the width is the square root of "x".
What would be the value of "x"?
What is the width of the rectangle?

Respuesta :

Answer:

Step-by-step explanation:

The area for a rectangle is A = LW. We know the area and we also know the length. We are solving for the width.

[tex]112=7\sqrt{x}[/tex] and

[tex]16=\sqrt{x}[/tex]

Siince the width is given as the square root of x, and the square root of x is equal to 16, then the width is 16. Now to find the value of x from the last statement in our equation. If

[tex]16=\sqrt{x}[/tex] and we want to solve for x, we will square both sides, since squaring undoes a square root. Since this is an equation, we have to square both sides.

256 = x

256 is the answer

lets take a closer look.. 4 sides are in in a rectangle, and we know the area and length:

112 x 2 = ? : 224

16 x 2 = ? : 32

244 + 32 = 256.

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