sethaltacount
sethaltacount
19-06-2020
Mathematics
contestada
64x^2 + 128x − 4y^2 + 32y + 256 = 0
Respuesta :
Victoriat4989
Victoriat4989
19-06-2020
Answer:
x=−1+
4
√
(y−12)(y+4)
,−1−
4
√
(y−12)(y+4)
Step-by-step explanation:
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