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Sian is twice as old as her sister Abigail. They divide 30 pounds in the ratio of their ages. How much do Sian and Abigail receive?

Respuesta :

Answer:

Sian would receive 20 Pounds while Abigail would receive 10 Pounds.

Step-by-step explanation:

Given that Sian is twice as old as her sister Abigail, it means that if Abigail's age is T years then Sian's age would be 2T years.

If they divide 30 pounds in the ratio of their ages, the ratio of their ages will be

T : 2T (Ratio of Abigail's gae to Sian's age)

The amount received by Abigail

= T/(T + 2T) × 30

= T/3T × 30

= 1/3 × 30

= 10 Pounds

The amount received by Sian

= 2T/(T + 2T) × 30

= 2T/3T × 30

= 2/3 × 30

= 20 Pounds

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