Question

Suppose Q and R are independent events. Find the probability of Q and R when P(Q)=0.41 ans P(R)=0.44.

Answer 1

we are given with two probabilities: P(Q) = 0.41 and P(R)  =0.44 in which events Q and R are non-mutually exclusive to each other. In this case, the probability of Q and R is equal to   P(Q)*  P(R) that is equivalent to 0.1804. This is the final answer to this problem.

Answer 2

Answer:

Probability of Q and R = 0.1804.

Step-by-step explanation:

Given : Q and R are independent events,when P(Q)=0.41 ans P(R)=0.44.

To find :  Find the probability of Q and R .

Solution : We have given that P(Q)=0.41 and P(R)=0.44. We need to find the probability of Q and R.

As we know Q , R are independent ,

Probability of Q and R = P(Q) * P(R)

Probability of Q and R = 0.41 * 0.44

Probability of Q and R = 0.1804.

Therefore , Probability of Q and R = 0.1804.