Respuesta :
well , we now the password would be :
3 _ _ _
and if there is no 0 and 9, the combination must be between 1 to 8
So the possibility of password would be :
8 x 8 x 8 = 512 possibilities
The answer is option B.
Hope this helps
3 _ _ _
and if there is no 0 and 9, the combination must be between 1 to 8
So the possibility of password would be :
8 x 8 x 8 = 512 possibilities
The answer is option B.
Hope this helps
If digits can be repeated, the number of possible passwords are 512
How to determine the number of passwords?
The given parameters are:
Usable digits = 8 i.e. no 0 and 9
First digit = 3
Length = 4
The above parameters mean that:
- The first digit can only be 1 digit
- The other digits can be any of the 8 digits
So, the number of passwords is:
Combination = 1 * 8 * 8 * 8
Evaluate
Combination = 512
Hence, if digits can be repeated, the number of possible passwords are 512
Read more about combination at:
https://brainly.com/question/11732255
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