Question

(08.02 MC)What is the mean absolute deviation for 9, 7, 6, 8, 7, and 5? 1 2 6 7 please answer in one minute please i am marking brainliest

Answer 1

Answer:

$M.A.D = 1$

Step-by-step explanation:

Given

9, 7, 6, 8, 7, 5

Required

Mean Absolute Deviation

The first step is to calculate the mean of the given data;

$Mean = \frac{\sum{x}}{n}$

where x = 9, 7, 6, 8, 7, 5 and n = 6

$Mean = \frac{9+ 7+ 6+ 8+ 7+ 5}{6}$

$Mean = \frac{42}{6}$

$Mean = 7$

Subtract mean (7) from each data

$9 - 7 = 2\\7 - 7 = 0\\6 - 7 = -1\\8 - 7 = 1\\7 - 7 = 0\\5 - 7 = -2$

Return the absolute values of each

$|2| = 2\\|0| = 0\\|-1| = 1\\|1| = 1\\|0| = 0\\|-2| =2$

Calculate mean of the above absolute values

$Mean = \frac{\sum{x}}{n}$

$Mean = \frac{2+0+1+1+0+2}{6}$

$Mean = \frac{6}{6}$

$Mean = 1$

Hence, the mean absolute deviation of the given data is 1