Answer: [tex]K_2SO_4\rightarrow 2K^++SO_4^{2-}[/tex]
concentration of [tex]K^+[/tex] = 0.50 M
concentration of [tex]SO_4^{2-}[/tex] = 0.25 M
Explanation:
The dissociation equation of [tex]K_2SO_4[/tex] is:
[tex]K_2SO_4\rightarrow 2K^++SO_4^{2-}[/tex]
According to stoichiometry:
1 mole of [tex]K_2SO_4[/tex] gives 2 moles of [tex]K^+[/tex]
Thus 0.25 moles of [tex]K_2SO_4[/tex] gives =[tex]\frac{2}{1}\times 0.25=0.50[/tex] moles of [tex]K^+[/tex]
Similarly,
1 mole of [tex]K_2SO_4[/tex] gives = 1 mole of [tex]SO_4^{2-}[/tex]
Thus 0.25 moles of [tex]K_2SO_4[/tex] gives =[tex]\frac{1}{1}\times 0.25=0.25[/tex] moles of [tex]SO_4^{2-}[/tex]
Thus the concentration of [tex]K^+[/tex] and [tex]SO_4^{2-}[/tex] are 0.50 M and 0.25 M respectively.
