Respuesta :
Answer:
The answer is the slope of XV is 1.
The slope of UW is -1
The slopes of the diagonals are negative reciprocals
The diagonals of kite UVWX are perpendicular
Step-by-step explanation:
Negative reciprocals in a kite create a perpendicular bisector. So the two lines share a midpoint so they are perpendicular.
One of the diagonal of a kite has a slope that is equal to the inverse
multiplied by (-1) of the other, therefore the diagonals are perpendicular
Reasons:
The proof that the diagonals of a kite are perpendicular is as follows;
The properties of a kite are;
The lengths of adjacent sides are equal
Therefore, taking the vertex at , U, as the origin, we have;
Coordinates of U = (0, 0)
Coordinates of V = (-a, b)
Coordinates of W = (0, c)
Coordinates of X = (a, b)
Step 1:
[tex]\displaystyle The \ slope \ of \ XV = \mathbf{ \frac{b - b}{x - (-x)} }=0[/tex]
The slope of XV is 0; XV is a horizontal line.
Step 2:
[tex]\displaystyle The \ slope \ of \ UW = \mathbf{\frac{c - 0}{0 - 0}} =\infty[/tex]
The slope of UW is infinity; UW is a vertical line.
Step 3:
The slope of the diagonals are; m₁ = 0, and m₂ = ∞
The above values satisfy the equation, [tex]\displaystyle m_2 = \mathbf{-\frac{1}{m_1}}[/tex]
Therefore;
- The diagonals of kite UVWX are perpendicular
Learn more about the characteristics of a kite here:
https://brainly.com/question/8843373
