Answer:
52°
Step-by-step explanation:
Since, measure of minor arc is equal to the measure of its corresponding central angle.
[tex] \therefore m\widehat{ED} = m\angle ECD\\
\because m\angle ECD = 104°\\
\purple {\bold {\therefore m\widehat{ED} = 104°}} \\[/tex]
Now by inscribed angle theorem:
[tex] m\angle EQD = \frac{1}{2} \times m\widehat{ED}\\\\
\therefore m\angle EQD = \frac{1}{2} \times 104°\\\\
\huge \red {\boxed {\therefore m\angle EQD = 52°}} \\[/tex]
