Question

write -4i+(1/4-5i)-(-3/4+8i)+17i as a complex number in the standard for

Answer 1

Answer:

$1+ 0i$

Step-by-step explanation:

A complex number is a number which has some real part and some imaginary part.

Standard form of a complex number is represented as

$a +bi$

Where $a$ is the real part,

and $bi$ is the imaginary part.

And $i = \sqrt{-1}$

Given complex number:

$-4i+\dfrac{1}{4}-5i)-(-\dfrac{3}{4}+8i)+17i\\\Rightarrow -4i+\dfrac{1}{4}-5i + \dfrac{3}{4}-8i+17i\\\Rightarrow \dfrac{3}{4}+\dfrac{1}{4}-4i -5i-8i+17i\\\Rightarrow \dfrac{3+1}{4}-17i+17i\\\Rightarrow \dfrac{4}{4}+0i\\\Rightarrow 1 + 0i$

Hence, the standard form is $1+ 0i$.