Answer:
A) After 2.5 milliseconds
Explanation:
Given that :
In a CAN bus, there are three computers: Computer A, Computer B, and Computer C.
Length in time of the message sent are 2 milliseconds long
As the computer start sending the message; the message are being sent at a message duration rate of 2 milliseconds
250 microseconds later, Computer B starts to send a message; There is a delay of 250 microseconds = 0.25 milliseconds here at Computer B
and 250 microseconds after that, Computer C starts to send a message
Similarly; delay at Computer C = 0.25 milliseconds
Assuming [tex]T_{RT}[/tex] is the retransmit time for Computer A to retransmit its message, Then :
[tex]T_{RT}[/tex] = [tex]T_A + T_B + T_C[/tex]
[tex]T_{RT}[/tex] = 2 milliseconds + 0.25 milliseconds + 0.25 milliseconds
[tex]T_{RT}[/tex] = 2.5 milliseconds
Thus; the correct option is A) After 2.5 milliseconds