Question

At STP, what is the volume in milliliters of 0.0395 mol of fluorine gas, F2?

Answer 1

Answer:

884.8 mL

Explanation:

If we have STP condition (Standard temperature and pressure), we will have the following relationship:

$1~mol=22.4~L$ or $1~mol=22400~mL$. With this in mind we can do the conversion:

$0.0395~mol\frac{22400~mL}{1~mol}=884.8~mL$

In the 0.0395 mol of fluorine gas, we will have 884.8 mL of gas at STP conditions.