Question

What volume will be occupied by 40.2 g of neon gas at STP?

Answer 1

Answer:

44.8 L

Explanation:

1 mole of a gas at s.t.p. occupies a volume of 22.4 L.

Molar mass of Neon is 20.1 g/mol

Number of moles of neon present in 40.2 g = Mass/molar mass

Number of moles = 40.2 / 20.1 = 2 moles.

Therefore, 2 moles of neon gas will occupy 2 * 22.4 L = 44.8 L

Answer 2

44.8 L

Molar mass of Neon is 20.1 g/mol

Number of moles of neon present in 40.2 g =$Mass/molar mass$

$Number of moles = 40.2 / 20.1 \\= 2 moles.$

At STP:-

Gases have a volume of 22.4L/mol.

Therefore, 2 moles of neon gas will occupy the volume is as follows:-

$2 mol\times22.4 L/mol = 44.8 L$

So, the volume is 44.8 L.

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