A glass rod that has been charged to +12.0 nC touches a metal sphere. Afterward, the rod's charge is +8.0 nC. a) What kind of charged particle was transferred between the rod and the sphere and in which direction? That is, did it move from rod to the sphere or from sphere to the rod? b) How many charged particles were transferred?

Respuesta :

Answer:

Explanation:

charge transferred to sphere = 12 - 8 = 4 nC

a )

The positive charge is decreased on glass rod , that means electrons must have entered the glass rod from the sphere which reduces its positive charge.

b )

charge transferred = 4 nC = 4 x 10⁻⁹ C

charge on one electron = 1.6 x 10⁻¹⁹ C

No of electrons transferred

= Total charge transferred / charge on one electron

= 4 x 10⁻⁹ / 1.6 x 10⁻¹⁹

= 2.5 x 10¹⁰ .

This question involves the concepts of charges and charged particles.

a) "Electrons" were transferred "from the sphere to the rod"

b) "2.5 x 10¹⁰" charged particles were transferred.

a)

Since the charge on the rod decreases by 4 nC. Therefore, negatively charged particles, that is electrons must have moved from the sphere to the rod. Because electrons are the mobile particles that move from one atom to the other.

b)

The number of charged particles transferred can be found using the following formula:

q = ne

where,

q = charge transferred = 4 nC = 4 x 10⁻⁹ C

n = no. of charged particles (electrons) transferred = ?

e = charge on one electron = 1.6 x 10⁻¹⁹ C

Therefore,

[tex]n=\frac{4\ x\ 10^{-9}\ C}{1.6\ x\ 10^{-19}\ C}[/tex]

n = 2.5 x 10¹⁰

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