Question

HELP!! PLEASE!! NEED DONE ASAP I WILL GIVE 100 POINTS AND MORE IF YOU CAN GET ALL 3 QUESTIONS DONE!! THANK YOU!! I WILL ALSO MARK BRAINLIST Kayson is looking at two buildings, building A and building B, at an angle of elevation of 73°. Building A is 30 feet away, and building B is 35 feet away. Which building is taller and by approximately how many feet? Building A; it is around 16.35 feet taller than building B Building A; it is around 114.48 feet taller than building B Building B; it is around 16.35 feet taller than building A Building B; it is around 114.48 feet taller than building A Look at the figure below: an image of a right triangle is shown with an angle labeled y If sin y° = a divided by 6 and tan y° = a divided by b, what is the value of cos y°? cos y° = 6 divided by b cos y° = 6a cos y° = 6b cos y° = b divided by 6 If sin f° = eight ninths and the measure of segment YW is 24 units, what is the measure of segment YX? triangle XYW in which angle W is a right angle, angle X measure f degrees, and angle Y measures d degrees 21 units 24 units 27 units 30 units

Answer 1

Answer:

I answered the questions but that formatting is very confusing and discourages anyone for trying to answer.

The last question is confusing. If I got it wrong, tell me. I will try to answer in the comment section then.

Step-by-step explanation:

Kayson is looking at two buildings, building A and building B, at an angle of elevation of 73°. Building A is 30 feet away, and building B is 35 feet away. Which building is taller and by approximately how many feet?

$\text{tan}\theta=\frac{h_{A}}{30} \Rightarrow h_{A}=\text{tan}73\º \cdot 30 \Rightarrow h_{A}\approx 98.12 \text{ feet}$

$\text{tan}\theta=\frac{h_{B}}{35} \Rightarrow h_{B}=\text{tan}73\º \cdot 35 \Rightarrow h_{B}\approx 114.47 \text{ feet}$

$\text{Difference} \approx 16.35$

Building B is around 16.35 feet taller than building A.

A Look at the figure below: an image of a right triangle is shown with an angle labeled y If sin y° = a divided by 6 and tan y° = a divided by b, what is the value of cos y°?

$\text{sin}(y)=\frac{a}{6}$

$\text{tan}(y)=\frac{a}{b}$

a is the opposite side; 6 is the hypotenuse; b is the adjacent side.

Therefore,

$\text{cos}(y)=\frac{b}{6}$

If sin f° = eight ninths and the measure of segment YW is 24 units, what is the measure of segment YX? triangle XYW in which angle W is a right angle, angle X measure f degrees, and angle Y measures d degrees.

This seems a bit confusing. The angles don't match. We have $90\º+62\º +21\º \approx 173\º$

$\text{sin}(f)=0.888...$

$f \approx 62\º$

YX is the hypotenuse of the right triangle.

$\text{cos}(21\º)=\frac{24}{YX}$

$YX \approx 25.7$

Considering $f \approx 69\º$

$\text{sin}(69\º)\approx\frac{24}{YX}$

$YX \approx 25.7$

Answer 2

Answer:

The third one is the answer

Building B; it is around 16.35 feet taller than building A

Look at the figure below: an image of a right triangle is shown with an angle labeled y If sin y° = a divided by 6 and tan y° = a divided by b, what is the value of cos y°?

cos y° = 6 divided by b cos y° = 6a cos

If sin f° = 8/9 and the measure of YW is 24 units, what is the measure of YX?

24 units