Question

3.

A body starts moving from rest and attains the acceleration of 0.5 m/s2. Calculate the
velocity at the end of 3 minutes and also find the distance travelled by it during that

time.
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Answer 1

Answer:

90 m/s

8100 m

Explanation:

Given:

v₀ = 0 m/s

a = 0.5 m/s²

t = 3 min = 180 s

Find: v and Δx

v = at + v₀

v = (0.5 m/s²) (180 s) + 0 m/s

v = 90 m/s

Δx = v₀ t + ½ at²

Δx = (0 m/s) (180 s) + ½ (0.5 m/s²) (180 s)²

Δx = 8100 m