Answer:
Null and alternative hypotheses:
H0: p1 = p2
H1: p1 ≠ p2
To find the sample proportions, we have the following:
[tex] p'1 = \frac{x_1}{n_1} = \frac{113}{3180} = 0.0355 [/tex]
[tex] p'2 = \frac{x_2}{n_2} = \frac{157}{3168} = 0.0495 [/tex]
[tex] p' = \frac{(x_1 + x_2}{n_1 + n_2} = \frac{113 + 157}{3180 + 3168} = 0.0425 [/tex]
Calculate Z statistics:
[tex]z = \frac{(p1 -p2)}{\sqrt{(p'(1-p')*(\frac{1}{n1}+ \frac{1}{n2})}}[/tex]
[tex]= \frac{(0.0355 - 0.0495)}{\sqrt{(0.0425*(1-0.0425) * (\frac{1}{3180} + \frac{1}{3168})}} = -2.764[/tex]
Z = -2.764
P-value = 0.00285
The pvalue is low.
Since the pvalue is low, reject null hypothesis, H0.
Conclusion:
There is strong evidence that patients experiencing the primary outcome is different for those receiving the treatment compared to those without