Question

A professor gives his students the choice of 7 assignments. Each student has to complete 4 of the 7 assignments.

How many combinations of the 4 assignments are possible?

Answer 1

Answer:

35 combinations

Step-by-step explanation:

$\frac{7!}{4! * 3!} = \frac{7*6*5*4!}{4! * 3*2*1} = 35$