Answer:
-10 is the correct answer to the given question .
Step-by-step explanation:
Missing information:
Following question is incomplete there is no information about the vertices and the rules .Following are the complete question that is mention below
Triangle PQR has vertices [tex]P(-2, 6), \ Q(-8, 4), and\ R(1, -2).[/tex] It is translated according to the rule [tex](x, y)\ -> \ (x\ - \ 2, y\ - 16)[/tex]. What is the y-value of P'?
Now coming to the solution as already mention in the question
The translated rule is [tex](x, y)\ -> (x - 2, \ y -16).[/tex]
Now calculated the vertices P value according to the rule of translated
[tex]P(-2, 6)\\Now \ apply \ the\ translated\ rule \ in\ P\ vertices\\P(-2, 6)->P1(-2-2,\ 6-16)\\P1->(-4,-10)[/tex]
So -10 is the value of y in P vertices .
