moralespascual210 moralespascual210
  • 16-06-2020
  • Mathematics
contestada

x^3+x²-36 Find all real zeros.

Respuesta :

MathTutors
MathTutors MathTutors
  • 16-06-2020

Answer: x=3

Step-by-step explanation:

To find the zeros, you want to first factor the expression.

x³+x²-36

(x-3)(x²+4x+12)

Now that we have found the factors, we set each to 0.

x-3=0

x=3

Since x²+4x+12 cannot be factored, we can forget about this part.

Therefore, the zeros are x=3. You can check this by plugging the expression into a graphing calculator to see the zeros.

Answer Link

Otras preguntas

What are the organelles of a cone cell?
write a program in pascal to solve a quadratic equation
write a program in pascal to solve a quadratic equation
Caitlyn did 6/7 of the problems on her math correctly and 4 incorrectly. She did all the problems. How many were there?
Name four behaviors that animals must use to survive
Caitlyn did 6/7 of the problems on her math correctly and 4 incorrectly. She did all the problems. How many were there?
Name four behaviors that animals must use to survive
Caitlyn did 6/7 of the problems on her math correctly and 4 incorrectly. She did all the problems. How many were there?
Peter jogged 96 yards in 40 seconds? What is his speed in feet per second?
Ned weighs 1.5 times as much as Jill and Tom weighs 15 kilograms more than Jill. If their combined weight is 190 kilograms, how much does each person weigh?