Answer:
16
Step-by-step explanation:
Given the nth term of a geometric sequence represented as [tex]Tn = a_1r^{n-1}[/tex]
[tex]a_1[/tex] = first term of the sequence
n = number of terms
r = common ratio
Given [tex]a_1 = 4,096,\ r = -\frac{1}{4} , n = 5[/tex](fifth term of the sequence)
[tex]T_5 = 4,096(-\frac{1}{4} )^{5-1}\\ T_5 = 4,096(-\frac{1}{4} )^{4}\\T_5 = 4,096(\frac{1}{256} )\\T_5 = 16[/tex]
The fifth term of the geometric sequence is 16
