Answer: f(y^2) = 1/((1/(x-3))^2-3)
Step-by-step explanation:
To start to understand this equation realize y = f(x) but f(x) gives a little bit more information specifically to define x as whatever is in the parenthesis of f(_).
For example f(x) = x/2
so lets say x = 2
so "f(2) = 2/2" or "y = 1 when x = 2"
In this equation y or f(x) = 1/(x-3)
so to get f(y^2) = 1/(x-3)
square the value of y and plug it into 1/(x-3) as the value of x
f(y^2) = 1/(y^2-3)
