Question

F(x) = 4√(2x³-1)
F'(x) =....?

Answer 1

$y= \sqrt[4]{(2x^3-1)} \\ y^4=2x^3-1 \\ 2x^3=y^4+1 \\ x^3= \frac{y^4+1}{2} \\ x= \sqrt[3]{\frac{y^4+1}{2}}$

Therefore, F'(x) = $\sqrt[3]{\frac{y^4+1}{2}}$