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caylus
Hello,

[tex]x^2+3x+3=0\\ \Delta=9-4*3=-3\\ x= \dfrac{-3-i*\sqrt{3}}{2} \ or\ x= \dfrac{-3+i*\sqrt{3}}{2} \\ [/tex]
[tex]x^2 + 3x + 3 = 0[/tex] 

[tex]Apply \ the \ Quadratic \ Formula[/tex] 

[tex] Given \ the \ general \ form \ ax^2+bx+c=0[/tex][tex]there \ exists \ two \ solutions \ where: a=1, b=3 \ and \ c=3[/tex] 

[tex]x= \dfrac{-3+ \sqrt{3i}}{2}, \dfrac{-3- \sqrt{3i} }{2} [/tex] 


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