Respuesta :
The equation that is applicable is as follows:
F = G * M * m ÷ r^2 F = G * M * m ÷ r^2
Weight = m * g
Weight = F m * g = G * M * m ÷ r^2 g = G * M ÷ r^2
Now you can determine the mass of the planet. For mars, r = 3,400,000 = 3.4 * 10^6 meters
0.38 = 6.67 * 10^-11 * M ÷ (3.4 * 10^6)^2 0.38 = 6.67 * 10^-11 * M ÷ 1.156 * 10^13
3.8 = 6.67 * 10^-11 * M ÷ (3.4 * 10^6)^2 0.38 = 6.67 * 10^-11 * M ÷ 1.156 * 10^13 Multiply both sides by 1.156 * 10^13
1.156 * 10^13 * 0.38 = 6.67 * 10^-11 * M Divide both sides by 6.67 * 10^-11
1.156 * 10^13 * 0.38 ÷ 6.67 * 10^-11 = M The answer is approximately 6.586 * 10^22 kg The actual mass of Mars is 6.42 * 10^23 kg. I think the acceleration of gravity on Mars is 3.8 m/s^2
1.156 * 10^13 * 3.8 ÷ 6.67 * 10^-11 = M The answer is approximately 6.586 * 10^23 kg
F = G * M * m ÷ r^2 F = G * M * m ÷ r^2
Weight = m * g
Weight = F m * g = G * M * m ÷ r^2 g = G * M ÷ r^2
Now you can determine the mass of the planet. For mars, r = 3,400,000 = 3.4 * 10^6 meters
0.38 = 6.67 * 10^-11 * M ÷ (3.4 * 10^6)^2 0.38 = 6.67 * 10^-11 * M ÷ 1.156 * 10^13
3.8 = 6.67 * 10^-11 * M ÷ (3.4 * 10^6)^2 0.38 = 6.67 * 10^-11 * M ÷ 1.156 * 10^13 Multiply both sides by 1.156 * 10^13
1.156 * 10^13 * 0.38 = 6.67 * 10^-11 * M Divide both sides by 6.67 * 10^-11
1.156 * 10^13 * 0.38 ÷ 6.67 * 10^-11 = M The answer is approximately 6.586 * 10^22 kg The actual mass of Mars is 6.42 * 10^23 kg. I think the acceleration of gravity on Mars is 3.8 m/s^2
1.156 * 10^13 * 3.8 ÷ 6.67 * 10^-11 = M The answer is approximately 6.586 * 10^23 kg
Mass of Mars is about 6.4 × 10²³ kg
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Further explanation
Let's recall the Gravitational Force formula:
[tex]\boxed {F = G\ \frac{m_1 m_2}{R^2}}[/tex]
where:
F = Gravitational Force ( N )
G = Gravitational Constant ( = 6.67 × 10⁻¹¹ Nm²/kg² )
m = mass of object ( kg )
R = distance between object ( m )
Let us now tackle the problem!
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Given:
acceleration of gravity at the surface of Earth = g₁
acceleration of gravity at the surface of Mars = g₂ = 0.38 g₁
radius of Mars = R₂ = 3400 km
radius of Earth = R₁ = 6400 km
mass of Earth = M₁ = 6 × 10²⁴ kg
Asked:
mass of Mars = M₂ = ?
Solution:
[tex]g_2 = 0.38 g_1[/tex]
[tex]G\frac{M_2}{(R_2)^2} = 0.38\ G \frac{M_1}{(R_1)^2}[/tex]
[tex]M_2 = 0.38\ (\frac{R_2}{R_1})^2 M_1[/tex]
[tex]M_2 = 0.38 \times (\frac{3400}{6400})^2 \times 6 \times 10^{24}[/tex]
[tex]M_2 \approx 6.4 \times 10^{23} \texttt{ kg}[/tex]
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Conclusion :
Mass of Mars is about 6.4 × 10²³ kg
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Learn more
- Unit of G : https://brainly.com/question/1724648
- Velocity of Runner : https://brainly.com/question/3813437
- Kinetic Energy : https://brainly.com/question/692781
- Acceleration : https://brainly.com/question/2283922
- The Speed of Car : https://brainly.com/question/568302
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Answer details
Grade: High School
Subject: Mathematics
Chapter: Gravitational Force
