Respuesta :
(a) Using upper right endpoints for each of the little 'grids' yields (with f(x,y) = xy)
∫∫R xy dA
≈ 2 * 2 [f(2, 10) + f(4, 10) + f(6, 10) + f(2, 12) + f(4, 12) + f(6, 12)]
= 4 [20 + 40 + 60 + 24 + 48 + 72]
= 1056.
(b) Using the midpoint for each of the little 'grids' yields
∫∫R xy dA
≈ 2 * 2 [f(1, 9) + f(3, 9) + f(5, 9) + f(1, 11) + f(3, 11) + f(5, 11)]
= 4 [9 + 27 + 45 + 11 + 33 + 55]
= 720.
∫∫R xy dA
≈ 2 * 2 [f(2, 10) + f(4, 10) + f(6, 10) + f(2, 12) + f(4, 12) + f(6, 12)]
= 4 [20 + 40 + 60 + 24 + 48 + 72]
= 1056.
(b) Using the midpoint for each of the little 'grids' yields
∫∫R xy dA
≈ 2 * 2 [f(1, 9) + f(3, 9) + f(5, 9) + f(1, 11) + f(3, 11) + f(5, 11)]
= 4 [9 + 27 + 45 + 11 + 33 + 55]
= 720.
The volume of the solid that lies below the surface z=xy and above the rectangle R by using Riemann sum is 288
Given that:
- R = {(x, y)} : 0 ≤ x ≤ 6 , 0 ≤ y ≤ 4}.
ᵃ₁ ᵇ₁ ᵃ₂ ᵇ₂
Let consider f(x,y) = z; for which the surface z = xy
where;
- m = 3 and n = 2
Then, the width of the region can be estimated by using the formula:
- [tex]\mathbf{\Delta x = \dfrac{b_1 -a_1}{m}}[/tex]
- [tex]\mathbf{\Delta x = \dfrac{6 -0}{3}}[/tex]
- [tex]\mathbf{\Delta x = 2}[/tex]
- [tex]\mathbf{\Delta y = \dfrac{b_2 -a_2}{m}}[/tex]
- [tex]\mathbf{\Delta y = \dfrac{4 -0}{2}}[/tex]
- [tex]\mathbf{\Delta y = 2}[/tex]
The endpoints are;
[tex]\mathbf{x_o = a_1 = 0; }\\ \\ \mathbf{ x_1 =x_o+\Delta x=2} \\ \\ \mathbf{x_2 =x_1+\Delta x=4 } \\ \\ \mathbf{x_3 =x_2+\Delta x = 6}[/tex]
[tex]\mathbf{y_o = a_2 = 0; }\\ \\ \mathbf{ y_1 =y_o+\Delta y=2} \\ \\ \mathbf{y_2 =y_1+\Delta y=4 } }[/tex]
The upper right regions are; { (2,2) , (2,4) , (4,2) , (4,4) , (6,2) , (6,4) }
Using the sample point to be the upper right corner of each square, the upper right endpoint is:
[tex]\mathbf{\iint_{r \ xydA} =\Delta x \times \Delta y} \mathbf{\Big[f(2,2)+f(2,4)+f(4,2)+f(4,4)+f(6,2)+f(6,4)\Big]}}[/tex]
[tex]\mathbf{=2\times 2} \mathbf{\Big[(2\times 2)+(2\times4)+ (4\times2)+ (4 \times 4)+(6 \times 2)+(6 \times4 )\Big]}}[/tex]
[tex]\mathbf{=4} \mathbf{\Big[4+8+8+ 16+12+24\Big]}}[/tex]
[tex]\mathbf{=4} \mathbf{\Big[72\Big]}}[/tex]
= 288
Learn more about Riemann sum here:
https://brainly.com/question/23960718?referrer=searchResults